7
Calling all Quick Charger 2.0 Owners on CM based 5.1.1 ROMs

  1. sfomin
    Nougat Sep 8, 2015

    sfomin , Sep 8, 2015 :
    Isnt it time = capacity/current? Where does the voltage come into the equation?
     

    #21
    HR_778 likes this.
  2. mwayner
    Lollipop Sep 8, 2015

    mwayner , Sep 8, 2015 :
    I'll update the CM12.1 rom and try again later today.
     

    #22
    HR_778 and Dr. Indest like this.
  3. Dr. Indest
    Lollipop Sep 8, 2015

    Dr. Indest , Sep 8, 2015 :
    Depends on what snapshot they used.
     

    #23
    HR_778 likes this.
  4. HR_778
    KitKat Sep 8, 2015


    #24
    AntMunny likes this.
  5. Dr. Indest
    Lollipop Sep 8, 2015

    Dr. Indest , Sep 8, 2015 :
    I think it is W=IA (If I recall from physics 6 years ago.... too lazy to google it lol)
     

    #25
    HR_778, Tobikage and sfomin like this.
  6. mwayner
    Lollipop Sep 8, 2015

    mwayner , Sep 8, 2015 :
    Doesn't seem so. I thought that might be the case but it reports the hdvcp file doesn't exist.
     

    #26
    HR_778 likes this.
  7. Tobikage
    Nougat Sep 8, 2015

    Tobikage , Sep 8, 2015 :
    Correct.

    I see 18W Qualcomm certified QC2.0 chargers on Amazon.
     

    #27
    sfomin and HR_778 like this.
  8. HR_778
    KitKat Sep 8, 2015

    HR_778 , Sep 8, 2015 :
    You may need to grab the latest CM12.1 Stable.
     

    #28
  9. Dr. Indest
    Lollipop Sep 8, 2015

    Dr. Indest , Sep 8, 2015 :
    hum... we don't even have
    /system/bin/hvdcp

    Anyone wants to help find the CM file?
     

    #29
    HR_778 likes this.
  10. Dr. Indest
    Lollipop Sep 8, 2015

    Dr. Indest , Sep 8, 2015 :
    meant W=IV Cause Amp is current :p....
     

    #30
    Tobikage likes this.
  11. sfomin
    Nougat Sep 8, 2015

    sfomin , Sep 8, 2015 :
    But I(A) = P(W)/ V(V)

    So 18W/9V=2 A of current.

    How is that any different than regular 2.0 A charger?
     

    #31
    Tobikage likes this.
  12. dustbunnyck
    Jelly Bean Sep 8, 2015

    dustbunnyck , Sep 8, 2015 :
    Less heat and it charges faster. Haha I have quick chargers on my note 4 It seems to charge cooler and in turn makes it charge faster as well. Opo charge makes the phone warmer
     

    #32
    sfomin likes this.
  13. sfomin
    Nougat Sep 8, 2015

    sfomin , Sep 8, 2015 :
    But both provide 2.0a current so they should charge at the same rate! I gotta look into this. I am missing something here
     

    #33
    Tobikage and HR_778 like this.
  14. Dr. Indest
    Lollipop Sep 8, 2015

    Dr. Indest , Sep 8, 2015 :
    I corrected my formula :p. Check my newer quotes.

    Also, I don't claim to like physics or even know it.... but to my understanding, Amps is the speed the voltage transfers at. So 2 Amps (which our charger is) * X voltage (higher Volt = more watts) = power.

    Again, took that class in 08 and hated it.
     

    #34
    Tobikage and HR_778 like this.
  15. Tobikage
    Nougat Sep 8, 2015

    Tobikage , Sep 8, 2015 :
    Total power output is measured in Watts right ?

    The OPO box charger is 5V and 2A correct ? So 10 Watts

    The Qualcomm site states the QC 2.0 chargers as 9V and 2Amps ie 18W or I'm too sleepy :p
     

    #35
    HR_778 likes this.
  16. dustbunnyck
    Jelly Bean Sep 8, 2015

    dustbunnyck , Sep 8, 2015 :
    The higher voltage helps to push it in faster. Most 2amp chargers rarely hit that amount, most sit about 1.5amps average throughout the charge, that's where the higher voltage is better.
     

    #36
    Tobikage, HR_778 and sfomin like this.
  17. Dr. Indest
    Lollipop Sep 8, 2015

    Dr. Indest , Sep 8, 2015 :
    I believe so. Been a while :p.
     

    #37
    Tobikage likes this.
  18. sfomin
    Nougat Sep 8, 2015

    sfomin , Sep 8, 2015 :
    Is that from experience? :p:D:D

    I gotta think about this sometime. For me 2 amps is 2 amps. i will take a look at it when i get a chance
     

    #38
  19. Dr. Indest
    Lollipop Sep 8, 2015

    Dr. Indest , Sep 8, 2015 :
    Only physics I claim to know is how to calculate total resistance..... and that is because the cardiovascular system requires it :p

    1/Rt = 1/R1 + 1/ R2 ... in parallel (system as a whole) and within organs, it is in series R1+R2... :p


    Oh and I know changing the resistance in an artery affects it 16 fold because it is 1/r^4 :p.
     

    #39
    rphlfjrd and Tobikage like this.
  20. dustbunnyck
    Jelly Bean Sep 8, 2015

    dustbunnyck , Sep 8, 2015 :
    The battery normally sits at 3.7v. When you're pushing at 9v the resistance is less so the amps are going through easier and less of it is turned off to heat. It's like having a box pushed by jockey then having it pushed by a body builder
     

    #40
    sfomin and Tobikage like this.